Chapter 3
Page 38
Chapter 4
Page 80
Problem 4.3(a): The conversions should be x’ = m ω x, y’ = m ω y, and z’ = m ω z.
Chapter 6
page 113
Eq. (6.23) should be
page 134
In the Thermodynamic Square box, the example used is dF but it should be dG. Thus,
dF = ( ) d p + ( ) dT
should be
dG = ( ) d p + ( ) dT
and after adding in the diagonal variables,
dF = V d p + S dT
should be
dG = V d p + S dT
Then with the proper signs,
dF = V d p – S dT
should be
dG = V d p – S dT
Page 138
Step 4 of the crushing procedure, κ is missing a minus sign.
page 152
Problem 6.5 should read: “in terms of T, v, α, and (∂α/∂T)p.”
Chapter 7
page 170
Eq. (7.28) should be η = W/Qh.
Chapter 8
Page 196
Figure 8.4(b): 2T should be T
page 202
In Exercise 8.16, Eq. (8.59) can be written as
page 206
Problem 8.6(c) dQ should have a slash through the d.
page 208
Problem 8.12(a), the final pressure should be in
terms of p and the volumes Vr and Vl.
Chapter 9
page 219
Eqs. (9.22) and (9.23) should have u0 in place of η.
Chapter 10
Page 264
Eq. (10.49) should be
page 279
Problem 10.23(c) should have answers in terms of ζ’, the single-particle partition function for the gaseous form of the substance.